CIDR2 Example

The ip address given is   as follows
97.201.50.188/27

Find the Network id, First host , last host and the broadcast address

1) Conversion and finding the subnet mask

97.201.50.188/27

27 1's
11111111.11111111.11111111.11100000

So we get  255.255.255.224

2) Find the increment
The increment is the last 1 
128,64,32
The last 1 is under the 32 column, so our increment is 32
 i = 32   { i is the increment }

3) Find the Network ID
The network ID is  found as below
97.201.50.0
97.201.50.32
97.201.50.64
97.201.50.96
97.201.50.128
97.201.50.160
97.201.50.192

As 192 is greater than 188,  The Network ID is going to be 97.201.50.160

4) Our first Host would be 1 more
97.201.50.161

5) Our last Host, would be last but 2, that is 97.201.50.190

6) Our broadcast address would be 1 less than  192 , so  97.201.50.191